Physics-Potential Difference
NEET Physics Potential Difference MCQ Question
Type: MCQ-numerical-Medium-Class 12
Two capacitors, C1 with capacitance 4 µF and C2 with capacitance 6 µF, are connected in series. If the potential difference across the combination is 120 V, what is the potential difference across C1?
A
48 V
B
72 V
C
60 V
D
80 V
Correct Answer
Option A
Detailed Explanation
In series, the potential difference is divided inversely to the capacitance values. Using V = V1 + V2, V1 = (C2 / (C1 + C2)) * V_total = (6 / (4 + 6)) * 120 = 48 V.
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