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Physics-Potential Difference

NEET Physics Potential Difference MCQ Question

Type: MCQ-diagram based-Hard-Class 12

Consider a parallel plate capacitor with plates separated by a distance d and a dielectric fully inserted between them. If the surface charge density on the plates is σ\sigma and the induced surface charge density on the dielectric is σp\sigma_p, which expression correctly gives the potential difference across the plates?

Question diagram
A

V=σdε0V = \frac{\sigma d}{\varepsilon_0}

B

V=(σ−σp)dε0V = \frac{(\sigma - \sigma_p) d}{\varepsilon_0}

C

V=σpdε0V = \frac{\sigma_p d}{\varepsilon_0}

D

V=σ(d−σp)ε0V = \frac{\sigma (d - \sigma_p)}{\varepsilon_0}

Correct Answer

Option B

Detailed Explanation

According to the NCERT context, the potential difference across the plates of a capacitor with a dielectric is given by V=(σ−σp)dε0V = \frac{(\sigma - \sigma_p) d}{\varepsilon_0}, where σ\sigma is the surface charge density on the plates and σp\sigma_p is the induced charge density on the dielectric.

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