NEET Physics (general) MCQ Question

The electrostatic energy stored in a capacitor is given by the formula $\frac{1}{2} C V^2$. Using $C = 12 \text{ pF}$ and $V = 50 \text{ V}$, the energy is $\frac{1}{2} \times 12 \times 10^{-12} \times (50)^2 \approx 1.5 \text{ \u00b5J}$.