Physics-(general)
NEET Physics (general) MCQ Question
Type: MCQ-numerical-Easy-Class 12
A parallel plate capacitor has a capacitance of 20 pF. If a dielectric slab with a dielectric constant of 4 is inserted completely between the plates, what will be the new capacitance?
A
80 pF
B
5 pF
C
60 pF
D
20 pF
Correct Answer
Option A
Detailed Explanation
The capacitance of a capacitor increases by a factor equal to the dielectric constant when a dielectric is inserted. Hence, 20 pF multiplied by 4 results in 80 pF.
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