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Physics-Electric Potential

NEET Physics Electric Potential MCQ Question

Type: MCQ-numerical-Easy-Class 12

A capacitor of 1000 pF is charged to a potential difference of 50 V. What is the electrostatic energy stored in the capacitor?

A

250˘0b5J25 \u00b5J

B

500˘0b5J50 \u00b5J

C

0.500˘0b5J0.50 \u00b5J

D

000˘0b5J00 \u00b5J

Correct Answer

Option A

Detailed Explanation

The energy stored in a capacitor is given by U=12CV2U = \frac{1}{2}CV^2. Substituting C=1000×10−12 FC = 1000 \times 10^{-12} \text{ F} and V=50 VV = 50 \text{ V}, the energy U=12×1000×10−12×502=1.25×10−6 JU = \frac{1}{2} \times 1000 \times 10^{-12} \times 50^2 = 1.25 \times 10^{-6} \text{ J} or 1.25 \u00b5J.

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