Physics-Electric Potential
NEET Physics Electric Potential MCQ Question
Type: MCQ-numerical-Medium-Class 12
What is the magnitude of the electric field between two closely spaced equipotential surfaces A and B, if the potential difference between them is 10 V and the distance is 0.5 m?
A
20 V/m
B
5 V/m
C
10 V/m
D
15 V/m
Correct Answer
Option A
Detailed Explanation
Using the relation |E| = -ΔV/Δl, the electric field magnitude is |E| = 10/0.5 = 20 V/m. This is derived from the relationship between field and potential.
Found an issue with this question?