NEET Physics Electric Potential MCQ Question
Consider two closely spaced equipotential surfaces A and B with potential values V and V + dV, respectively, where dV represents the change in potential in the direction of the electric field E. If the perpendicular distance between these surfaces is dl, what is the expression for the magnitude of the electric field E?
E = |dV| / dl
E = dV / dl
E = dl / dV
E = -dV / dl
Correct Answer
Detailed Explanation
The electric field E is related to the potential difference dV and the distance dl as E = -dV / dl, which accounts for the work done in moving a unit positive charge between the equipotential surfaces.
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