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Physics-Maxwell's Equations

NEET Physics Maxwell's Equations MCQ Question

Type: MCQ-numerical-Medium-Class 12

Given that the speed of light is approximately 3×1083 \times 10^8 m/s, calculate the angular frequency ω\omega of an electromagnetic wave with a wavelength λ\lambda of 500 nm.

A

77×1015 rad/s77 \times 10^{15} \text{ rad/s}

B

36×1015 rad/s36 \times 10^{15} \text{ rad/s}

C

88×1015 rad/s88 \times 10^{15} \text{ rad/s}

D

6.00×1015 rad/s6.00 \times 10^{15} \text{ rad/s}

Correct Answer

Option C

Detailed Explanation

Using the relation c=λuc = \lambda u and u=ω2π u = \frac{\omega}{2\pi}, we find ω=2πcλ\omega = \frac{2\pi c}{\lambda}. Substituting c=3×108c = 3 \times 10^8 m/s and λ=500×10−9\lambda = 500 \times 10^{-9} m, we get ω=1.88×1015\omega = 1.88 \times 10^{15} rad/s.

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