Physics-Motional EMF
NEET Physics Motional EMF MCQ Question
Type: MCQ-numerical-Hard-Class 12
A straight conductor of length 5 m is moving perpendicular to a uniform magnetic field of 0.5 T with a speed of 4 m/s. What is the magnitude of the motional emf developed across the conductor?
A
10 V
B
5 V
C
2 V
D
20 V
Correct Answer
Option A
Detailed Explanation
The motional emf is given by the formula emf = Blv, where B is the magnetic field, l is the length of the conductor, and v is the speed. Substituting the values, we get emf = 0.5 T * 5 m * 4 m/s = 10 V.
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