Physics-Motional EMF
NEET Physics Motional EMF MCQ Question
Type: MCQ-numerical-Hard-Class 12
A straight conductor of length 10 m moves perpendicularly to a uniform magnetic field of 0.30 × 10⁻⁴ Wb/m² with a speed of 5.0 m/s. What is the magnitude of the motional emf induced in the conductor?
A
5 × 10⁻³ V
B
5 × 10⁻⁴ V
C
0.15 V
D
15 V
Correct Answer
Option A
Detailed Explanation
The motional emf is calculated using the formula emf = Bvl, where B is the magnetic field, v is the velocity, and l is the length of the conductor. Substituting the given values: emf = (0.30 × 10⁻⁴ Wb/m²)(5.0 m/s)(10 m) = 1.5 × 10⁻³ V.
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