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Physics-Motional EMF

NEET Physics Motional EMF MCQ Question

Type: MCQ-numerical-Medium-Class 12

A straight conductor of length 0.5 m is moving with a velocity of 20 m/s perpendicular to a uniform magnetic field of 0.1 T. What is the magnitude of the motional emf induced across the ends of the conductor?

A

0 V

B

0 V

C

0.5 V

D

0.1 V

Correct Answer

Option A

Detailed Explanation

The motional emf is calculated using the formula ε=Bvl\varepsilon = Bvl, where BB is the magnetic field, vv is the velocity, and ll is the length of the conductor. Substituting the given values, ε=0.1×20×0.5=1.0\varepsilon = 0.1 \times 20 \times 0.5 = 1.0 V.

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