NEET Physics Photoelectric Effect MCQ Question
A metal surface emits electrons when illuminated by light of frequency 8.0 × 10^14 Hz. If the threshold frequency for the metal is 5.0 × 10^14 Hz, what is the maximum kinetic energy of the emitted electrons? (Use Planck's constant h = 6.63 × 10^-34 J s)
1.99 × 10^-19 J
3.31 × 10^-19 J
5.30 × 10^-19 J
2.65 × 10^-19 J
Correct Answer
Detailed Explanation
The maximum kinetic energy of emitted electrons is given by K.E. = h(f - f0), where f is the frequency of incident light and f0 is the threshold frequency. Substituting the given values, K.E. = 6.63 × 10^-34 × (8.0 × 10^14 - 5.0 × 10^14) = 1.99 × 10^-19 J.
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