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Physics-(general)

NEET Physics (general) MCQ Question

Type: MCQ-numerical-Easy-Class 12

What is the threshold frequency for a material with a work function of 3.20 eV?

A

7.72 x 10^14 Hz

B

5.16 x 10^14 Hz

C

4.84 x 10^14 Hz

D

6.63 x 10^14 Hz

Correct Answer

Option A

Detailed Explanation

The threshold frequency u0 u_0 is calculated using the formula u0=ϕh u_0 = \frac{\phi}{h}, where ϕ=3.20 eV=3.20×1.6×10−19 J\phi = 3.20 \text{ eV} = 3.20 \times 1.6 \times 10^{-19} \text{ J} and h=6.63×10−34 Jsh = 6.63 \times 10^{-34} \text{ Js}. Thus, u0=3.20×1.6×10−196.63×10−34=7.72×1014 Hz u_0 = \frac{3.20 \times 1.6 \times 10^{-19}}{6.63 \times 10^{-34}} = 7.72 \times 10^{14} \text{ Hz}.

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