Physics-(general)

NEET Physics (general) MCQ Question

Type: MCQ-numerical-Medium-Class 12

If two cells with emfs ε1=2 V\varepsilon_1 = 2 \text{ V} and ε2=3 V\varepsilon_2 = 3 \text{ V} are connected in series with internal resistances r1=0.5Ωr_1 = 0.5 \Omega and r2=0.3Ωr_2 = 0.3 \Omega, what is the total emf of the combination?

A

5 V

B

8 V

C

4 V

D

5.3 V

Correct Answer

Option A

Detailed Explanation

When cells are connected in series, the total emf is the sum of the individual emfs: εtotal=ε1+ε2=2 V+3 V=5 V\varepsilon_{total} = \varepsilon_1 + \varepsilon_2 = 2 \text{ V} + 3 \text{ V} = 5 \text{ V}.

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