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Physics-(general)

NEET Physics (general) MCQ Question

Type: MCQ-numerical-Medium-Class 12

Two cells with emfs ε1\varepsilon_1 and ε2\varepsilon_2 are connected in series with internal resistances r1r_1 and r2r_2 respectively. If the total current flowing through the circuit is II, what is the total voltage across the cells?

A

ε1+ε2−I(r1+r2)\varepsilon_1 + \varepsilon_2 - I(r_1 + r_2)

B

ε1+ε2+I(r1+r2)\varepsilon_1 + \varepsilon_2 + I(r_1 + r_2)

C

ε1−ε2−I(r1+r2)\varepsilon_1 - \varepsilon_2 - I(r_1 + r_2)

D

ε1−ε2+I(r1+r2)\varepsilon_1 - \varepsilon_2 + I(r_1 + r_2)

Correct Answer

Option A

Detailed Explanation

In a series circuit, the total voltage is the sum of the emfs minus the voltage drops across the internal resistances, which is I(r1+r2)I(r_1 + r_2).

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