Physics-Power in AC Circuits
NEET Physics Power in AC Circuits MCQ Question
Type: MCQ-diagram based-Medium-Class 12
Consider a series RLC circuit where an AC voltage source v = v_m sin ωt is applied. The current in the circuit is given by i = i_m sin(ωt + φ). Which of the following correctly describes the expression for the average power dissipated in the circuit over a full cycle?
A
P = V * I * cos φ
B
P = V * I * sin φ
C
P = V * I * tan φ
D
P = V * I * cot φ
Correct Answer
Option A
Detailed Explanation
The average power dissipated in an AC circuit is given by P = V * I * cos φ, where φ is the phase difference between the voltage and current. This is derived from the relation for average power: P = (V_m * I_m * cos φ) / 2.
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