NEET2022Physics-Work, Energy and Power
NEET 2022 Physics Power MCQ Question
Type: MCQ-numerical-Medium-Class 11
An electric lift with a maximum load of 2000 kg (lift + passengers) is moving up with a constant speed of 1.5 m s⁻¹. The frictional force opposing the motion is 3000 N. The minimum power delivered by the motor to the lift in watts is: (g = 10 m s⁻²)
A
34500
B
23500
C
23000
D
20000
Correct Answer
Option A
Detailed Explanation
The power is calculated using P = Fv, where F is the total force (weight + friction). Substituting the values, P = 34500 W.
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