NEET Physics Transverse & Longitudinal Waves MCQ Question
A wire stretched between two rigid supports vibrates at its fundamental frequency of 45 Hz. If the mass of the wire is 3.5 × 10^-2 kg, what should be the tension in the wire for a length of 1.5 meters?
45 N
67.5 N
90 N
135 N
Correct Answer
Detailed Explanation
The fundamental frequency of a stretched wire is given by f = (1/2L)√(T/μ), where L is the length, T is the tension, and μ is the mass per unit length. Solving for T with L = 1.5 m, f = 45 Hz, and μ = mass/length = 3.5 × 10^-2 kg / 1.5 m gives T = 67.5 N.
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