NEET Physics Transverse & Longitudinal Waves MCQ Question
A wire stretched between two rigid supports vibrates at its fundamental frequency of 45 Hz. If the mass of the wire is 3.5 × 10^-2 kg, what should be the tension in the wire for a length of 1.5 meters?
45 N
67.5 N
90 N
135 N
Correct Answer
Detailed Explanation
The fundamental frequency of a stretched wire is given by f = (1/2L)√(T/μ), where L is the length, T is the tension, and μ is the mass per unit length. Solving for T with L = 1.5 m, f = 45 Hz, and μ = mass/length = 3.5 × 10^-2 kg / 1.5 m gives T = 67.5 N.
Found an issue with this question?
Related Questions
More from Transverse & Longitudinal Waves
A diagram shows a wave in a solid medium with particles oscillating perpendicular to the direction of wave propagation. Which type of wave is being de...
Which of the following combinations about transverse and longitudinal waves is correct?
A diagram shows a wave traveling along a stretched string. The particle motion is depicted perpendicular to the direction of wave propagation. Which t...
More from
What does the variable 'a' represent in the wave motion equation y(x, t) = a sin(kx - ωt)?
A diagram depicts a sinusoidal wave traveling along the positive x-axis. The wave is described by the equation y(x, t) = a sin(kx - ωt + φ). What does...
Assertion (A): The wavelength of a wave is the distance between two consecutive points having the same phase. | Reason (R): In a sinusoidal wave, the ...