NEET Physics Standing Waves MCQ Question
A standing wave is formed on a string fixed at both ends with a length of 1.2 m. If the speed of the wave on the string is 60 m/s, what is the frequency of the second harmonic?
50 Hz
25 Hz
75 Hz
100 Hz
Correct Answer
Detailed Explanation
For a string fixed at both ends, the frequency of the nth harmonic is given by f_n = nv/(2L). For the second harmonic, n = 2, so f_2 = 260/(2*1.2) = 50 Hz.
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