Steam at 100 °C is passed into 20 g of water at 10 °C. When water acquires a temperature of 80 °C, the mass of water present will be (Take specific heat of water = 1 cal g⁻¹ °C⁻¹ and latent heat of steam = 540 cal g⁻¹)
A
24 g
B
31.5 g
C
42.5 g
D
22.5 g

Question

Steam at 100 °C is passed into 20 g of water at 10 °C. When water acquires a temperature of 80 °C, the mass of water present will be (Take specific heat of water = 1 cal g⁻¹ °C⁻¹ and latent heat of steam = 540 cal g⁻¹)

A

24 g

B

31.5 g

C

42.5 g

D

22.5 g

Accepted Answer

31.5 g

Answer

24 g

Answer

42.5 g

Answer

22.5 g

NEET 2014 Physics Calorimetry MCQ Question

Correct Answer

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