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NEET2022Physics-Radius of Gyration

NEET 2022 Physics Radius of Gyration MCQ Question

Type: MCQ-numerical-Medium-Class 11

The ratio of the radius of gyration of a thin uniform disc about an axis passing through its centre and normal to its plane to the radius of gyration of the disc about its diameter is:

A

4 : 1

B

1 : √2

C

2 : 1

D

√2 : 1

Correct Answer

Option D

Detailed Explanation

Chapter: System of Particles and Rotational Motion Class: 11 Physics — Chapter 6 Topic: Radius of Gyration Difficulty: 🟡 Medium

✅ Ans: D — 2:1\sqrt2:1

Radius of gyration:

k=IMk=\sqrt{\frac{I}{M}}

For a disc about an axis normal to its plane:

I1=12MR2I_1=\frac12MR^2 k1=R2k_1=\frac{R}{\sqrt2}

About its diameter:

I2=14MR2I_2=\frac14MR^2 k2=R2k_2=\frac{R}{2}

Therefore,

k1k2=R/2R/2=2\frac{k_1}{k_2} =\frac{R/\sqrt2}{R/2} =\sqrt2 k1:k2=2:1\boxed{k_1:k_2=\sqrt2:1}

📌 Key formulas: Disc: I⊥=12MR2I_{\perp}=\frac12MR^2, Idiameter=14MR2I_{\text{diameter}}=\frac14MR^2. (medicneet.com)

🧠 NEET Trick: For radius of gyration, take square root of I/MI/M. Don't directly compare moments of inertia.

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