NEET 2022 Physics Center of Mass MCQ Question

Chapter: System of Particles and Rotational Motion

Class: 11 Physics Topic: Centre of Mass Difficulty: 🟡 Medium

✅ Ans: D — $\frac{20}{3}\,m$

Take the 10 kg mass as $x=0$. The 20 kg mass is at $x=10\,m$.

$$x_{CM}=\frac{m_1x_1+m_2x_2}{m_1+m_2}$$ $$x_{CM}=\frac{10(0)+20(10)}{10+20} =\frac{200}{30} =\boxed{\frac{20}{3}\,m}$$

📌 The centre of mass is closer to the heavier 20 kg mass.

Note: The screenshot marks C = $10/3$ m, but that is the distance from the 20 kg mass. Since the question asks distance from the 10 kg mass, the correct answer is D = $20/3$ m.