Physics-Time Period & Frequency
NEET Physics Time Period & Frequency MCQ Question
Type: MCQ-numerical-Medium-Class 11
A simple pendulum has a length such that its time period is 2 seconds. If the acceleration due to gravity is 9.8 m/s², what is the approximate length of the pendulum?
A
0.98 m
B
1.12 m
C
2.45 m
D
3.92 m
Correct Answer
Option A
Detailed Explanation
Using the formula T = 2π√(L/g) and given T=2s, g=9.8 m/s², we calculate L = gT²/4π² = 0.98 m.
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