Physics-Time Period & Frequency
NEET Physics Time Period & Frequency MCQ Question
Type: MCQ-numerical-Medium-Class 11
A particle undergoes simple harmonic motion with a spring constant of 200 N/m and a mass of 2 kg. Calculate the time period of oscillation.
A
0.63 s
B
26 s
C
52 s
D
0.91 s
Correct Answer
Option B
Detailed Explanation
The time period T is given by T = 2π√(m/k). Substituting m = 2 kg and k = 200 N/m, we get T = 2π√(2/200) = 1.26 s.
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