Physics-Time Period & Frequency
NEET Physics Time Period & Frequency MCQ Question
Type: MCQ-numerical-Hard-Class 11
A simple pendulum has a length of 2.5 m. Calculate the time period of the pendulum assuming small amplitude oscillations. (Take g = 9.8 m/s²)
A
17 s
B
52 s
C
01 s
D
26 s
Correct Answer
Option A
Detailed Explanation
The time period T of a simple pendulum is given by T = 2π√(L/g). Substituting L = 2.5 m and g = 9.8 m/s², T = 2π√(2.5/9.8) = 3.17 s.
Found an issue with this question?
Related Questions
More from Time Period & Frequency
More from
Assertion (A): The acceleration in simple harmonic motion is always directed towards the mean position. | Reason (R): In simple harmonic motion, accel...
Simple Harmonic MotionPhysics
Consider a block attached to a spring on a frictionless surface, as described in the context. If the displacement of the block from the wall is given ...
(general)Physics
What is the relationship between the driving frequency and the amplitude of an oscillator in Simple Harmonic Motion?
Simple Harmonic MotionPhysics