NEET2024Physics-Oscillations
NEET 2024 Physics Simple Pendulum MCQ Question
Type: MCQ-numerical-Medium-Class 11
If the mass of the bob in a simple pendulum is increased to thrice its original mass and its length is made half its original length, then the new time period of oscillation is x/2 times its original time period. Then the value of x is:
A
2√3
B
4
C
√3
D
√2
Correct Answer
Option D
Detailed Explanation
The time period of a pendulum is T = 2π√(L/g). If the length is halved, T' = 2π√(L/2g) = T/√2. Thus, x = 4.
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