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Physics-Simple Harmonic Motion

NEET Physics Simple Harmonic Motion MCQ Question

Type: MCQ-diagram based-Medium-Class 11

Consider a simple pendulum where the angular displacement θ is small. Which of the following best represents the relationship between angular acceleration α and angular displacement θ?

Question diagram
A

α = −mgL/I θ

B

α = mgL/I sin θ

C

α = −mgL/I sin θ

D

α = mgL/I θ

Correct Answer

Option A

Detailed Explanation

For small angular displacements, sin θ can be approximated by θ, and the relationship between angular acceleration α and angular displacement θ is given by α = −mgL/I θ, indicating a proportional and opposite relationship.

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