NEET Physics Simple Harmonic Motion MCQ Question
Consider a simple pendulum where the angular displacement θ is small. Which of the following best represents the relationship between angular acceleration α and angular displacement θ?
α = −mgL/I θ
α = mgL/I sin θ
α = −mgL/I sin θ
α = mgL/I θ
Correct Answer
Detailed Explanation
For small angular displacements, sin θ can be approximated by θ, and the relationship between angular acceleration α and angular displacement θ is given by α = −mgL/I θ, indicating a proportional and opposite relationship.
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