Physics-Simple Harmonic Motion
NEET Physics Simple Harmonic Motion MCQ Question
Type: MCQ-numerical-Hard-Class 11
A block of mass m is attached to a spring with spring constant k and executes simple harmonic motion with amplitude A. What is the total mechanical energy of the system?
A
0.5 * k * A^2
B
m * A^2 / 2
C
k * A^2 / 4
D
m * k * A^2
Correct Answer
Option A
Detailed Explanation
The total mechanical energy of a simple harmonic oscillator is given by E = 0.5 * k * A^2, where k is the spring constant and A is the amplitude.
Found an issue with this question?
Related Questions
More from Simple Harmonic Motion
More from
What happens to the mechanical energy of a damped oscillator during its motion?
Damped & Forced OscillationsPhysics
Assertion (A): The time period of an oscillator is inversely proportional to the square root of the spring constant. | Reason (R): A stiff spring corr...
Time Period & FrequencyPhysics
What is the mathematical representation of the displacement of a particle in simple harmonic motion?
(general)Physics