NEET Physics Simple Harmonic Motion MCQ Question
In the diagram shown above, if the block of mass m is executing simple harmonic motion on a spring with spring constant k, which expression correctly represents the maximum velocity of the block?
v_max = ωA
v_max = A/k
v_max = ω^2 A
v_max = A/ω
Correct Answer
Detailed Explanation
The maximum velocity in simple harmonic motion is given by v_max = ωA, where ω is the angular frequency and A is the amplitude of motion, as per the NCERT context.
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