NEET Physics Simple Harmonic Motion MCQ Question
A block of mass 0.5 kg is attached to a spring with a spring constant of 200 N/m. What is the time period of the simple harmonic motion executed by the block-spring system?
0.31 s
0.63 s
00 s
25 s
Correct Answer
Detailed Explanation
The time period of a mass-spring system in simple harmonic motion is given by T = 2π√(m/k). Substituting m = 0.5 kg and k = 200 N/m, we get T = 2π√(0.5/200) = 0.63 s.
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