Physics-Simple Harmonic Motion
NEET Physics Simple Harmonic Motion MCQ Question
Type: MCQ-numerical-Easy-Class 11
A block of mass 0.5 kg is attached to a spring with a spring constant of 200 N/m. What is the time period of the simple harmonic motion executed by the block-spring system?
A
0.31 s
B
0.63 s
C
00 s
D
25 s
Correct Answer
Option B
Detailed Explanation
The time period of a mass-spring system in simple harmonic motion is given by T = 2π√(m/k). Substituting m = 0.5 kg and k = 200 N/m, we get T = 2π√(0.5/200) = 0.63 s.
Found an issue with this question?
Related Questions
More from Simple Harmonic Motion
More from
What happens to the mechanical energy of a damped oscillator during its motion?
Damped & Forced OscillationsPhysics
Assertion (A): The time period of an oscillator is inversely proportional to the square root of the spring constant. | Reason (R): A stiff spring corr...
Time Period & FrequencyPhysics
What is the mathematical representation of the displacement of a particle in simple harmonic motion?
(general)Physics