NEET Physics Simple Harmonic Motion MCQ Question
A block of mass 5 kg is attached to a spring with a spring constant of 500 N/m. If the amplitude of the motion is 0.1 m, what is the maximum acceleration of the block during its simple harmonic motion?
10 m/s²
100 m/s²
1 m/s²
50 m/s²
Correct Answer
Detailed Explanation
The maximum acceleration in SHM is given by a_max = ω²A, where ω = √(k/m). Here, k = 500 N/m, m = 5 kg, and A = 0.1 m. Thus, ω = √(500/5) = √100 = 10 rad/s, and a_max = 10² × 0.1 = 100 m/s².
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