Physics-Simple Harmonic Motion
NEET Physics Simple Harmonic Motion MCQ Question
Type: MCQ-numerical-Easy-Class 11
A particle is executing simple harmonic motion with a period of 30 seconds and an amplitude of 5 meters. What is the angular speed (ω) of the particle?
A
0.21 rad/s
B
0.42 rad/s
C
1.57 rad/s
D
3.14 rad/s
Correct Answer
Option B
Detailed Explanation
The angular speed ω is given by ω = 2π/T. With a period T = 30 s, ω = 2π/30 = 0.42 rad/s.
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