NEET Physics Simple Harmonic Motion Match the Following Question
Match Column-I with Column-II.
| Column-I | Column-II |
|---|---|
| (a) Maximum speed | (i) –ω²x(t) |
| (b) Displacement | (ii) Aω |
| (c) Maximum acceleration | (iii) A sin(ωt + φ) |
| (d) Velocity function | (iv) A cos(ωt + φ) |
a-ii, b-iii, c-i, d-iv
a-i, b-iv, c-ii, d-iii
a-ii, b-iv, c-i, d-iii
a-ii, b-iii, c-iv, d-i
Correct Answer
Detailed Explanation
The maximum speed in simple harmonic motion is given by v_m = Aω, where A is the amplitude and ω is the angular frequency. The displacement at time t can be expressed as x(t) = A sin(ωt + φ). The acceleration is given by a(t) = –ω²x(t), and the velocity function is v(t) = Aω cos(ωt + φ).
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