Physics-Simple Harmonic Motion

NEET Physics Simple Harmonic Motion Match the Following Question

Type: Match the Following-match the column-Hard-Class 11

Match Column-I with Column-II.

Column-I Column-II (a) Maximum speed (i) –ω²x(t) (b) Displacement (ii) Aω (c) Maximum acceleration (iii) A sin(ωt + φ) (d) Velocity function (iv) A cos(ωt + φ)

Choose the correct matching:

A

a-ii, b-iii, c-i, d-iv

B

a-i, b-iv, c-ii, d-iii

C

a-ii, b-iv, c-i, d-iii

D

a-ii, b-iii, c-iv, d-i

Correct Answer

Option A

Detailed Explanation

The maximum speed in simple harmonic motion is given by v_m = Aω, where A is the amplitude and ω is the angular frequency. The displacement at time t can be expressed as x(t) = A sin(ωt + φ). The acceleration is given by a(t) = –ω²x(t), and the velocity function is v(t) = Aω cos(ωt + φ).

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