NEET2022Physics-Oscillations
NEET 2022 Physics Simple Harmonic Motion MCQ Question
Type: MCQ-numerical-Medium-Class 11
Two pendulums of length 121 cm and 100 cm start vibrating in phase. At some instant, the two are at their mean position in the same phase. The minimum number of vibrations of the shorter pendulum after which the two are again in phase at the mean position is:
A
10
B
8
C
11
D
9
Correct Answer
Option A
Detailed Explanation
The time period of a pendulum is proportional to the square root of its length. The ratio of the time periods is √(121/100) = 1.1. Therefore, after 10 vibrations of the shorter pendulum, they will be in phase.
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