NEET 2015 Physics Kinematics MCQ Question
A particle of unit mass undergoes one-dimensional motion such that its velocity varies according to v(x) = βxⁿ, where β and n are constants and x is the position of the particle. The acceleration of the particle as a function of x, is given by
−2nβ²xⁿ⁻¹
−2nβ²xⁿ⁺¹
−2β²xⁿ⁺¹
−2nβ²xⁿ⁺¹
Correct Answer
Detailed Explanation
The acceleration is the derivative of velocity with respect to time, which involves differentiating v(x) with respect to x and multiplying by v(x). This results in −2nβ²xⁿ⁻¹.
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