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Physics-Projectile Motion

NEET Physics Projectile Motion MCQ Question

Type: MCQ-diagram based-Hard-Class 11

Consider a projectile launched from the origin with an initial velocity v₀ at an angle θ₀ with the horizontal axis. Which of the following expressions correctly represents the time of flight Tₓ when the projectile lands back on the same horizontal level?

Question diagram
A

Tₓ = (2v₀ sin θ₀)/g

B

Tₓ = v₀ sin θ₀/g

C

Tₓ = (v₀ cos θ₀)/g

D

Tₓ = (v₀/g)(1 + sin θ₀)

Correct Answer

Option A

Detailed Explanation

The time of flight Tₓ for a projectile is given by Tₓ = 2(v₀ sin θ₀)/g, as derived from setting the vertical displacement to zero and using the vertical motion equation.

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