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Physics-Projectile Motion

NEET Physics Projectile Motion MCQ Question

Type: MCQ-diagram based-Hard-Class 11

Consider a projectile launched with an initial velocity vov_o at an angle θo\theta_o with the horizontal. Using the equation y=tan⁡(θo)x−g2vo2cos⁡2(θo)x2y = \tan(\theta_o)x - \frac{g}{2v_o^2\cos^2(\theta_o)}x^2, which of the following correctly describes the path of the projectile?

Question diagram
A

The trajectory is a parabola due to the quadratic term.

B

The trajectory is a linear path due to the tan⁡(θo)x\tan(\theta_o)x term.

C

The trajectory is a circle due to the gravitational force.

D

The trajectory is elliptical due to the horizontal component.

Correct Answer

Option A

Detailed Explanation

The equation y=tan⁡(θo)x−g2vo2cos⁡2(θo)x2y = \tan(\theta_o)x - \frac{g}{2v_o^2\cos^2(\theta_o)}x^2 represents a parabola, indicating the path of the projectile is parabolic as given in the NCERT text.

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