NEET Physics Projectile Motion MCQ Question
A projectile is launched with an initial velocity of 20 m/s at an angle of 30 degrees with the horizontal. What is the horizontal distance covered by the projectile when it returns to the ground level? (Assume g = 9.8 m/s²)
34.6 m
50.0 m
23.4 m
39.2 m
Correct Answer
Detailed Explanation
The horizontal distance (range) R can be calculated using the formula R = (v₀² * sin(2θ)) / g, where v₀ is the initial velocity, θ is the projection angle, and g is the acceleration due to gravity. Substituting the given values, R = (20² * sin(60)) / 9.8, which results in approximately 50.0 m.
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