Physics-Projectile Motion
NEET Physics Projectile Motion MCQ Question
Type: MCQ-numerical-Hard-Class 11
A projectile is launched from the origin with an initial velocity v_0 at an angle θ_0 with the horizontal. If h_max is the maximum height reached by the projectile, which of the following expressions correctly represents h_max?
A
(v_0^2 * sin^2(θ_0)) / (2g)
B
(v_0^2 * cos^2(θ_0)) / (2g)
C
(v_0 * sin(θ_0)) / g
D
(v_0^2) / (2g * tan(θ_0))
Correct Answer
Option A
Detailed Explanation
The maximum height h_max of a projectile is given by the vertical component of the initial velocity squared, divided by two times the acceleration due to gravity: h_max = (v_0^2 * sin^2(θ_0)) / (2g).
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