NEET Physics Kinetic Interpretation of Temperature MCQ Question
If the root mean square speed of nitrogen gas molecules at 300 K is 516 m/s, what will be the root mean square speed of oxygen gas molecules at the same temperature? (Consider the molar masses of nitrogen and oxygen as 28 g/mol and 32 g/mol respectively.)
483 m/s
516 m/s
540 m/s
600 m/s
Correct Answer
Detailed Explanation
The root mean square speed is inversely proportional to the square root of the molar mass for gases at the same temperature. Since oxygen is heavier than nitrogen, its rms speed is lower: v_rms of O2 = v_rms of N2 * sqrt(28/32) = 516 m/s * sqrt(28/32) = 483 m/s.
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