Physics-Kinetic Interpretation of Temperature
NEET Physics Kinetic Interpretation of Temperature MCQ Question
Type: MCQ-numerical-Hard-Class 11
Given that the mean square speed of nitrogen molecules at 300 K is 516 m²/s², calculate the root mean square (rms) speed of argon atoms at the same temperature, knowing that the molecular mass of nitrogen (N₂) is 28 u and argon (Ar) is 39.9 u.
A
431 m/s
B
516 m/s
C
652 m/s
D
694 m/s
Correct Answer
Option A
Detailed Explanation
The rms speed is inversely proportional to the square root of the molecular mass. Thus, v_rms(Ar) = v_rms(N₂) * sqrt(M(N₂)/M(Ar)) = 516 * sqrt(28/39.9) ≈ 431 m/s.
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