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Physics-(general)

NEET Physics (general) MCQ Question

Type: MCQ-numerical-Hard-Class 11

Given a gas mixture where the mass densities of two gases are ρ1=0.947 kg/m3\rho_1 = 0.947 \text{ kg/m}^3 and ρ2=0.6 kg/m3\rho_2 = 0.6 \text{ kg/m}^3, with molecular masses M1M_1 and M2M_2 respectively, what is the correct relationship between M1M2\frac{M_1}{M_2} and ρ1ρ2\frac{\rho_1}{\rho_2}?

A

M1M2=ρ1ρ2\frac{M_1}{M_2} = \frac{\rho_1}{\rho_2}

B

M1M2=(ρ1ρ2)2\frac{M_1}{M_2} = \left(\frac{\rho_1}{\rho_2}\right)^2

C

M1M2=(ρ2ρ1)\frac{M_1}{M_2} = \left(\frac{\rho_2}{\rho_1}\right)

D

M1M2=ρ2ρ1\frac{M_1}{M_2} = \frac{\rho_2}{\rho_1}

Correct Answer

Option A

Detailed Explanation

The relationship M1M2=ρ1ρ2\frac{M_1}{M_2} = \frac{\rho_1}{\rho_2} is derived from the fact that μ=mM\mu = \frac{m}{M} and that the mass density ρ=mV\rho = \frac{m}{V}, implying MV=ρ\frac{M}{V} = \rho.

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