NEETPhysics-Circular Motion
NEET Physics Centripetal Acceleration MCQ Question
Type: MCQ-numerical-Medium
A stone tied to the end of a string 100 cm long is whirled in a horizontal circle with a constant speed. If the stone makes 14 revolutions in 22 s, then the acceleration of the stone is
A
16 m s⁻²
B
4 m s⁻²
C
12 m s⁻²
D
8 m s⁻²
Correct Answer
Option A
Detailed Explanation
The centripetal acceleration is given by a = v²/r. Calculate the speed using the number of revolutions and time, then use the radius to find the acceleration.
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