In the first excited state of hydrogen atom, the energy of its electron is −3.4 eV. The radial distance of the electron from the hydrogen nucleus in this case is approximately:
(Take 1 eV = 1.6 × 10⁻¹

Question

In the first excited state of hydrogen atom, the energy of its electron is −3.4 eV. The radial distance of the electron from the hydrogen nucleus in this case is approximately:
(Take 1 eV = 1.6 × 10⁻¹⁹ J, e = 1.6 × 10⁻¹⁹ C and $ \frac{1}{4\pi\varepsilon_0} = 9 \times 10^9 \text{ N m}^2/\text{C}^2 $)

Accepted Answer

2.1 × 10⁻¹⁰ m

Answer

2.1 × 10⁻⁹ m

Answer

2.1 × 10⁻⁸ m

Answer

2.1 × 10⁻¹¹ m

NEET 2026 Physics Bohr Model of Hydrogen Atom MCQ Question

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