NEET Chemistry Raoult's Law MCQ Question
In an ideal solution of two volatile liquids A and B, the mole fraction of A is 0.3 and its pure component vapor pressure is 80 mmHg. If the mole fraction of B is 0.7 and its pure component vapor pressure is 100 mmHg, what is the total vapor pressure of the solution according to Raoult's Law?
86 mmHg
94 mmHg
92 mmHg
88 mmHg
Correct Answer
Detailed Explanation
According to Raoult's Law, the total vapor pressure is the sum of the partial pressures: P_total = x_A * P_A^0 + x_B * P_B^0 = 0.3 * 80 + 0.7 * 100 = 94 mmHg.
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