Chemistry-Raoult's Law
NEET Chemistry Raoult's Law MCQ Question
Type: MCQ-numerical-Medium-Class 12
In an ideal solution of two volatile liquids A and B, the mole fraction of A is 0.3 and its pure component vapor pressure is 80 mmHg. If the mole fraction of B is 0.7 and its pure component vapor pressure is 100 mmHg, what is the total vapor pressure of the solution according to Raoult's Law?
A
86 mmHg
B
94 mmHg
C
92 mmHg
D
88 mmHg
Correct Answer
Option B
Detailed Explanation
According to Raoult's Law, the total vapor pressure is the sum of the partial pressures: P_total = x_A * P_A^0 + x_B * P_B^0 = 0.3 * 80 + 0.7 * 100 = 94 mmHg.
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