NEET Chemistry Raoult's Law MCQ Question
For a binary ideal solution at a certain temperature, the vapour pressure of pure component A is 100 mmHg and that of pure component B is 80 mmHg. If the mole fraction of A in the solution is 0.4, what is the total vapour pressure of the solution?
88 mmHg
92 mmHg
84 mmHg
80 mmHg
Correct Answer
Detailed Explanation
According to Raoult's law, the total vapour pressure P_total = x_A * P_A^0 + x_B * P_B^0. With x_A = 0.4, P_A^0 = 100 mmHg, and x_B = 0.6, P_B^0 = 80 mmHg, the total vapour pressure is 0.4 * 100 + 0.6 * 80 = 88 mmHg.
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