Chemistry-(general)
NEET Chemistry (general) MCQ Question
Type: MCQ-numerical-Easy-Class 12
What is the mole fraction of CHCl3 in the solution prepared by mixing 25.5 g of CHCl3 and 40 g of CH2Cl2 at 298 K?
A
0.312
B
0.468
C
0.213
D
0.532
Correct Answer
Option A
Detailed Explanation
The mole fraction of CHCl3 is calculated by dividing the moles of CHCl3 by the total moles in the solution. Moles of CHCl3 are 0.213, and total moles are 0.683, so the mole fraction is 0.213/0.683 = 0.312.
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