Chemistry-(general)
NEET Chemistry (general) MCQ Question
Type: MCQ-numerical-Easy-Class 12
If 10 grams of a solute is dissolved in 90 grams of water and the depression in the freezing point is found to be 0.93 K, what is the molar mass of the solute? Given Kf for water is 1.86 K kg mol^-1.
A
20.0 g/mol
B
40.0 g/mol
C
60.0 g/mol
D
80.0 g/mol
Correct Answer
Option B
Detailed Explanation
Using the formula M2 = (Kf * w1 * 1000) / (w2 * ΔTf), substituting the given values: M2 = (1.86 * 90 * 1000) / (10 * 0.93) which simplifies to 40.0 g/mol.
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