NEET Chemistry Organic Preparations MCQ Question
In the reaction where 6NaI reacts with 4H₂SO₄ to produce 3I₂, 4H₂O, S, and 3Na₂SO₄, how many moles of iodine (I₂) will be produced if 0.5 moles of NaI are used?
0.25 moles
0.5 moles
0.75 moles
1.0 moles
Correct Answer
Detailed Explanation
From the stoichiometry of the reaction 6NaI + 4H₂SO₄ → 3I₂ + 4H₂O + S + 3Na₂SO₄, 6 moles of NaI produce 3 moles of I₂. Therefore, 0.5 moles of NaI will produce (0.5/6)*3 = 0.25 moles of I₂.
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