NEET Chemistry Organic Preparations MCQ Question
In the reaction 2NaI + MnO2 + 2H2SO4 → I2 + MnSO4 + Na2SO4 + 2H2O, if 0.5 moles of NaI are used, how many moles of iodine (I2) will be produced?
0.25 moles
0.5 moles
1 mole
0.75 moles
Correct Answer
Detailed Explanation
The stoichiometry of the reaction shows that 2 moles of NaI produce 1 mole of I2. Therefore, 0.5 moles of NaI will produce 0.25 moles of I2.
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